![SOLVED: Initial mass of the sample (CuSO4 * xHO) before beating 0.21349 Final mass of anhydrous salt after heating Time needed t0 reach t0 the final constant mass S41uLes Calculations: Show setups; SOLVED: Initial mass of the sample (CuSO4 * xHO) before beating 0.21349 Final mass of anhydrous salt after heating Time needed t0 reach t0 the final constant mass S41uLes Calculations: Show setups;](https://cdn.numerade.com/ask_images/f4899685cdc54b4ea2f90d7979228250.jpg)
SOLVED: Initial mass of the sample (CuSO4 * xHO) before beating 0.21349 Final mass of anhydrous salt after heating Time needed t0 reach t0 the final constant mass S41uLes Calculations: Show setups;
![A 5.0 g sample of Cu (NO(3))(2).n (H(2)O) is heated, and 3.9 g of anhydrous salt remains. What is the value of 'n' ? Cu(NO(3))(2),n(H(2)O)overset(Delta)toCu(NO(3))(2)+nH(2)O A 5.0 g sample of Cu (NO(3))(2).n (H(2)O) is heated, and 3.9 g of anhydrous salt remains. What is the value of 'n' ? Cu(NO(3))(2),n(H(2)O)overset(Delta)toCu(NO(3))(2)+nH(2)O](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/644044155_web.png)
A 5.0 g sample of Cu (NO(3))(2).n (H(2)O) is heated, and 3.9 g of anhydrous salt remains. What is the value of 'n' ? Cu(NO(3))(2),n(H(2)O)overset(Delta)toCu(NO(3))(2)+nH(2)O
![One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol ^-1 of heat. The value of Δ H(hydration) of AB is - 29.4 J mol ^-1 . The One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol ^-1 of heat. The value of Δ H(hydration) of AB is - 29.4 J mol ^-1 . The](https://dwes9vv9u0550.cloudfront.net/images/2861486/604a1c67-fc7d-46ee-9eed-c9328de3fbe0.jpg)
One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol ^-1 of heat. The value of Δ H(hydration) of AB is - 29.4 J mol ^-1 . The
![SOLVED: Formula (Molar) mass of anhydrous salt (on bottle) Number of grams of HzO per 100.0 g hydrate *49 14.8 Number of moles HzO per 100.0 g hydrate 1q.8 18.0 Da moles SOLVED: Formula (Molar) mass of anhydrous salt (on bottle) Number of grams of HzO per 100.0 g hydrate *49 14.8 Number of moles HzO per 100.0 g hydrate 1q.8 18.0 Da moles](https://cdn.numerade.com/ask_images/722e57774e06473a9151c1a912f8e846.jpg)
SOLVED: Formula (Molar) mass of anhydrous salt (on bottle) Number of grams of HzO per 100.0 g hydrate *49 14.8 Number of moles HzO per 100.0 g hydrate 1q.8 18.0 Da moles
![One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol^-1 of heat. The value of ΔHydration AB is - 29.4 J mol^-1 . The heat of dissolution of One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol^-1 of heat. The value of ΔHydration AB is - 29.4 J mol^-1 . The heat of dissolution of](https://toppr-doubts-media.s3.amazonaws.com/images/6720124/78c19904-67c5-4c0c-8411-c308417aa9c8.jpg)
One mole of anhydrous salt AB dissolves in water and librates 21.0 J mol^-1 of heat. The value of ΔHydration AB is - 29.4 J mol^-1 . The heat of dissolution of
3 anhydrous salt to be 208.3 g. Using Equation 2, determine the number of moles of the anhydrous salt. Equation 2 Number of mol
One mole of anhydrous salt AB dissolves inwater and liberates 15 J mol 1 of heat. The value ofdrs fon of AB is 20.5 J mol 1. Hence, the enthalpyof dissolution of
![5 g of crystalline salt, when rendered anhydrous, lost 1.89 g of water. The formula weight of anhydrous salts is 160 . The number of molecules of water of crystallisation in the salt is: 5 g of crystalline salt, when rendered anhydrous, lost 1.89 g of water. The formula weight of anhydrous salts is 160 . The number of molecules of water of crystallisation in the salt is:](https://dwes9vv9u0550.cloudfront.net/images/1872266/5eca5d71-7e9a-435c-90fa-efc2518fec05.jpg)